RE: LeoThread 2025-12-24 22-14
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Find the total number of zeros in the product of 1 × 2× 3 × ................ × 250?
0
0
0.000
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The number of trailing zeros in 250! is the number of times the product can be divided by 10 (each 10 comes from a factor of 2 × 5, with 5s being the limiting factor).
Count the multiples of 5 up to 250:
⌊250/5⌋ = 50
⌊250/25⌋ = 10
⌊250/125⌋ = 2
⌊250/625⌋ = 0
Total: 50 + 10 + 2 = 62.
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